A 10 capacitor is connected to a 210 V, 50 Hz source as shown in figure. The peak current in the circuit is nearly ( = 3.14) : [figure]
- 0.58 A
- 0.93 A
- 1.20 A
- 0.35 A
Answer
(2) 0.93 A
Solution
Capacitive reactance:
XC = 12 f C = 12 3.14 50 10 10-6
XC = 10431.4 318.5
210 V is the rms voltage, so Irms = VrmsXC = 210318.5 0.66 A
I0 = 2 Irms = 1.414 0.66 0.93 A
Answer: (2)