Let A= bmatrix1 & 3 & -1\ 2 & 1 & \ 0 & 1 & -1 bmatrix be a singular matrix. Let f(x)= 0x (t2+2t+3 )dt, x [1, ]. If M and m are respectively the maximum and the minimum values of f in [1, ], then 3(M-m) is equal to :
- 64
- 68
- 72
- 76
Answer
(2) 68
Solution
A is singular |A|=0
1(-1- )-3(-2-0)+(-1)(2-0)=0
3- =0 =3
f'(x)=x2+2x+3=(x+1)2+2>0 f is increasing on [1, 3]
M=f(3), m=f(1)
M-m= 13 (t2+2t+3 )dt= [ t33+t2+3t ]13
M-m=27- 133= 683
3(M-m)=68
Answer: (2)