Xg of ethylamine is subjected to reaction with NaNO2/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP. X is 10-1 g.
Answer
45
Solution
C2H5NH2 NaNO2/HCl C2H5N2+Cl- H2O C2H5OH + N2 + HCl
∵ 1 mol amine gives 1 mol N2
Moles of N2 = 2.2422.4 = 0.1 mol ⇒ amine = 0.1 mol
Molar mass of C2H5NH2 = 45 g mol-1
∴ X = 0.1 × 45 = 4.5 g = 45 × 10-1 g
Answer: 45