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Aldehydes, Ketones and Carboxylic Acids · Question 22

NEET (UG) 2022 (Phase 2)MCQMedium📈 Topic in 50% papers+4−1
1

The products A and B in the following reaction sequence are : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(3) [figure]

Solution

Step 1 (Markovnikov addition; the more stable benzylic carbocation is formed):

C6H5-CH=CH2 HBr C6H5-CH(Br)-CH3

Step 2 (Grignard reagent):

C6H5-CH(Br)-CH3 Mg, dry ether C6H5-CH(MgBr)-CH3

Step 3 (carboxylation; as per NCERT, Grignard reagents react with CO2 to give, after hydrolysis, carboxylic acids):

C6H5-CH(MgBr)-CH3 [(ii) H3O+](i) CO2 C6H5-CH(CH3)-COOH = A

Step 4 (acid chloride, then amide):

A SOCl2 C6H5-CH(CH3)-COCl

CH3NH2 C6H5-CH(CH3)-CONHCH3 = B

∴ A = 2-phenylpropanoic acid and B = N-methyl-2-phenylpropanamide, as in option (3).

Answer: (3)

NEET (UG) 2022 (Phase 2)

Keep practising — Aldehydes, Ketones and Carboxylic Acids

2

The incorrect method to synthesize benzaldehyde is

  1. [figure] , CH3MgBr, followed by H3O+
  2. [figure] , H2, Pd-BaSO4
  3. [figure] , DIBAL-H, followed by H2O
  4. [figure] , CrO2Cl2 in CS2, followed by H3O+
NEET (UG) 2022 (Phase 2)
3

Match List-I with List-II Choose the correct answer from the options given below.

  1. (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
  2. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
  3. (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
  4. (a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
NEET (UG) 2021
4

The intermediate compound 'X' in the following chemical reaction is : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET (UG) 2021
5

The product formed in the following chemical reaction is : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET (UG) 2021
6

Identify compound X in the following sequence of reactions : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET (UG) 2020
7

Reaction between benzaldehyde and acetophenone in presence of dilute NaOH is known as :

  1. Cannizzaro's reaction
  2. Cross Cannizzaro's reaction
  3. Cross Aldol condensation
  4. Aldol condensation
NEET (UG) 2020
8

The major product of the following reaction is : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET (UG) 2019
9

Compound A, C8H10O, is found to react with NaOI (produced by reacting Y with NaOH) and yields a yellow precipitate with characteristic smell. A and Y are respectively

  1. [figure] and I2
  2. [figure] and I2
  3. [figure] and I2
  4. [figure] and I2
NEET 2018
10

Carboxylic acids have higher boiling points than aldehydes, ketones and even alcohols of comparable molecular mass. It is due to their

  1. formation of intramolecular H-bonding
  2. formation of carboxylate ion
  3. more extensive association of carboxylic acid via van der Waals' forces of attraction
  4. formation of intermolecular H-bonding
NEET 2018
11

Of the following, which is the product formed when cyclohexanone undergoes aldol condensation followed by heating?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET 2017

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