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Chemical Bonding and Molecular Structure · Question 23

JEE Main 2025 (Online) 7th April Morning ShiftMatchingEasy📈 Topic in 32% papers+4−1
1

Match the List I with List II. Choose the correct answer from the options given below:

  1. A-IV, B-III, C-II, D-I
  2. A-III, B-IV, C-I, D-II
  3. A-II, B-I, C-IV, D-III
  4. A-III, B-IV, C-II, D-I

Answer

(4) A-III, B-IV, C-II, D-I

Solution

Bond pairs (σ and π pairs) : lone pairs on the central atom —

A. ICl2-: I has 7 + 1 = 8 valence electrons; 2 I–Cl bonds use 2, leaving 6 = 3 lone pairs 2 : 3 (III)

B. H2O: 2 O–H bond pairs, 2 lone pairs 2 : 2 (IV)

C. SO2 (O=S=O): two double bonds = 4 bond pairs; S (6 valence electrons) is left with 1 lone pair 4 : 1 (II)

D. XeF4: 4 Xe–F bond pairs; Xe (8 valence electrons) is left with 2 lone pairs 4 : 2 (I)

A-III, B-IV, C-II, D-I

Answer: (4)

JEE Main 2025 (Online) 7th April Morning Shift

Keep practising — Chemical Bonding and Molecular Structure

2

In SO2, NO2- and N3-, the hybridizations at the central atom are respectively :

  1. sp2, sp2 and sp2
  2. sp, sp2 and sp
  3. sp2, sp and sp
  4. sp2, sp2 and sp
JEE Main 2025 (Online) 7th April Evening Shift
3

Which of the following molecule(s) show/s paramagnetic behavior? Choose the correct answer from the options given below:

  1. A & C only
  2. A & E Only
  3. A & D Only
  4. B Only
JEE Main 2025 (Online) 4th April Morning Shift
4

Given below are two statements: In the light of the above statements, choose the most appropriate answer from the options given below:

  1. Both Statement I and Statement II are correct
  2. Both Statement I and Statement II are incorrect
  3. Statement I is correct but Statement II is incorrect
  4. Statement I is incorrect but Statement II is correct
JEE Main 2025 (Online) 4th April Evening Shift
5

Match the LIST-I with LIST-II Choose the correct answer from the options given below:

  1. A-IV, B-I, C-II, D-III
  2. A-III, B-I, C-IV, D-II
  3. A-II, B-III, C-IV, D-I
  4. A-I, B-II, C-III, D-IV
JEE Main 2025 (Online) 3rd April Morning Shift
6

Given below are two statements: In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are false
  2. Both Statement I and Statement II are true
  3. Statement I is false but Statement II is true
  4. Statement I is true but Statement II is false
JEE Main 2025 (Online) 3rd April Evening Shift
7

A molecule with the formula AX4Y has all its elements from p-block. Element A is rarest, monoatomic, non-radioactive from its group and has the lowest ionization enthalpy value among A, X and Y. Elements X and Y have first and second highest electronegativity values respectively among all the known elements. The shape of the molecule is:

  1. Pentagonal planar
  2. Square pyramidal
  3. Trigonal bipyramidal
  4. Octahedral
JEE Main 2025 (Online) 2nd April Morning Shift
8

Among SO2, NF3, NH3, XeF2, ClF3 and SF4, the hybridization of the molecule with nonzero dipole moment and highest number of lone-pairs of electrons on the central atom is

  1. sp3
  2. dsp2
  3. sp3d2
  4. sp3d
JEE Main 2025 (Online) 2nd April Morning Shift
9

Which among the following molecules is (a) involved in sp3d hybridization, (b) has different bond lengths and (c) has lone pair of electrons on the central atom?

  1. XeF4
  2. XeF2
  3. PF5
  4. SF4
JEE Main 2025 (Online) 2nd April Evening Shift
10

An element 'E' has the ionisation enthalpy value of 374 kJ mol-1. 'E' reacts with elements A, B, C and D with electron gain enthalpy values of −328, −349, −325 and −295 kJ mol-1, respectively. The correct order of the products EA, EB, EC and ED in terms of ionic character is :

  1. EB > EA > EC > ED
  2. EA > EB > EC > ED
  3. ED > EC > EA > EB
  4. ED > EC > EB > EA
JEE Main 2025 (Online) 29th January Morning Shift
11

The sum of sigma ( ) and pi ( ) bonds in Hex-1,3-dien-5-yne is .

JEE Main 2025 (Online) 29th January Morning Shift

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