A healthy person eats the following diet – 5 g raw sugar, 4 g albumin, 10 g pure buffalo ghee adulterated with 2 g vegetable ghee (hydrogenated vegetable oil) and 5 g lignin. How many calories he is likely to get?
- 126
- 164
- 112
- 144
Answer
(4) 144
Solution
Physiological fuel values: carbohydrate = 4 kcal g-1, protein = 4 kcal g-1, fat = 9 kcal g-1; lignin is not digested by humans (0).
Raw sugar: 5 4 = 20
Albumin: 4 4 = 16
Ghee (fat): (10 + 2) 9 = 108
Lignin: 0
Total = 20 + 16 + 108 = 144 calories (kcal)
Answer: (4)