A(g) B(g) + C2(g) The correct relationship between KP, and equilibrium pressure P is
- KP = 1/2P3/2(2+ )3/2
- KP = 3/2P1/2(2+ )1/2(1- )
- KP = 1/2P1/2(2+ )3/2
- KP = 1/2P1/2(2+ )1/2
Answer
(2) KP = 3/2P1/2(2+ )1/2(1- )
Solution
Start with 1 mol A; at equilibrium: A = 1- , B = , C = 2
⇒ total moles = 1+ 2= 2+ 2
Partial pressure = mole fraction × P:
pA= 2(1- )P2+ , pB= 2 P2+ , pC= P2+
KP= pB pC1/2pA
= 1- ( P2+ )1/2
= 3/2P1/2(2+ )1/2(1- )
Answer: (2)