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Waves · Question 19

AIPMT 2015MCQMedium📈 Topic in 50% papers+4−1
1

The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second overtone of an organ pipe open at both the ends. The length of organ pipe open at both the ends is

  1. 120 cm
  2. 140 cm
  3. 80 cm
  4. 100 cm

Answer

(1) 120 cm

Solution

Closed pipe (fundamental): = v4Lc = v4 20 = v80

Open pipe, second overtone = third harmonic: ' = 3v2Lo

= ' v80 = 3v2Lo

Lo = 3 802 = 120 cm

Answer: (1)

AIPMT 2015

Keep practising — Waves

2

A source of sound S emitting waves of frequency 100 Hz and an observer O are located at some distance from each other. The source is moving with a speed of 19.4 m s-1 at an angle of 60 with the source observer line as shown in the figure. The observer is at rest. The apparent frequency observed by the observer (velocity of sound in air 330 m s-1), is [figure]

  1. 106 Hz
  2. 97 Hz
  3. 100 Hz
  4. 103 Hz
Out of syllabusAIPMT 2015
3

If n1, n2 and n3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by

  1. 1n = 1n1 + 1n2 + 1n3
  2. 1 n = 1 n1 + 1 n2 + 1 n3
  3. n = n1 + n2 + n3
  4. n = n1 + n2 + n3
AIPMT 2014
4

The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are (Velocity of sound = 340 m s-1)

  1. 4
  2. 5
  3. 7
  4. 6
AIPMT 2014
5

A speeding motorcyclist sees traffic jam ahead of him. He slows down to 36 km hour-1. He finds that traffic has eased and a car moving ahead of him at 18 km hour-1 is honking at a frequency of 1392 Hz. If the speed of sound is 343 m s-1, the frequency of the honk as heard by him will be

  1. 1332 Hz
  2. 1372 Hz
  3. 1412 Hz
  4. 1454 Hz
Out of syllabusAIPMT 2014
6

If we study the vibration of a pipe open at both ends, then the following statement is not true.

  1. All harmonics of the fundamental frequency will be generated.
  2. Pressure change will be maximum at both ends.
  3. Open end will be antinode.
  4. Odd harmonics of the fundamental frequency will be generated.
NEET 2013
7

A wave travelling in the +ve x-direction having displacement along y-direction as 1 m, wavelength 2 m and frequency of 1 Hz is represented by

  1. y = sin(10 x - 20 t)
  2. y = sin(2 x + 2 t)
  3. y = sin(x - 2t)
  4. y = sin(2 x - 2 t)
NEET 2013
8

A source of unknown frequency gives 4 beats/s when sounded with a source of known frequency 250 Hz. The second harmonic of the source of unknown frequency gives five beats per second, when sounded with a source of frequency 513 Hz. The unknown frequency is

  1. 240 Hz
  2. 260 Hz
  3. 254 Hz
  4. 246 Hz
NEET 2013
9

The length of the wire between two ends of a sonometer is 100 cm. What should be the positions of two bridges below the wire so that the three segments of the wire have their fundamental frequencies in the ratio 1 : 3 : 5.

  1. 150023 cm, 50023 cm
  2. 150023 cm, 30023 cm
  3. 30023 cm, 150023 cm
  4. 150023 cm, 200023 cm
NEET 2013 (Karnataka)
10

Two sources P and Q produce notes of frequency 660 Hz each. A listener moves from P to Q with a speed of 1 m s-1. If the speed of sound is 330 m/s, then the number of beats heard by the listener per second will be

  1. 4
  2. 8
  3. 2
  4. zero
Out of syllabusNEET 2013 (Karnataka)
11

The equation of a simple harmonic wave is given by y = 3 2(50t - x), where x and y are in metres and t is in seconds. The ratio of maximum particle velocity to the wave velocity is

  1. 2
  2. 32
  3. 3
  4. 23
AIPMT 2012 (Mains)

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