A string is stretched between fixed points separated by 75.0 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. The lowest resonant frequency for this string is
- 10.5 Hz
- 105 Hz
- 155 Hz
- 205 Hz
Answer
(2) 105 Hz
Solution
For a string fixed at both ends, n = n 1 (n = 1, 2, 3, …)
The two frequencies are consecutive harmonics:
n+1 - n = 1
1 = 420 - 315 = 105 Hz
(Check: 315 = 3 105, 420 = 4 105)
Answer: (2)