Let a, b C. Let , be the roots of the equation x2+ax+b=0. If - = 11 and 2- 2=3i 11, then ( 3- 3 )2 is equal to:
- 160
- 176
- 194
- 187
Answer
(2) 176
Solution
2- 2=( - )( + )
+ = 3i 11 11=3i
( + )2-( - )2=4
4 =(3i)2-11=-9-11=-20 =-5
2+ + 2=( + )2- =-9+5=-4
Now 3- 3=( - ) ( 2+ + 2 )= 11 (-4)
( 3- 3 )2=11 16=176
Answer: (2)