Let S=\z C : z2+4z+16=0\. Then z S |z+ 3 i |2 is equal to :
- 42
- 23
- 27
- 38
Answer
(4) 38
Solution
z2+4z+16=0 z= -4 16-642=-2 2 3 i
For z1=-2+2 3 i: z1+ 3 i=-2+3 3 i
|z1+ 3 i |2=4+27=31
For z2=-2-2 3 i: z2+ 3 i=-2- 3 i
|z2+ 3 i |2=4+3=7
z S |z+ 3 i |2=31+7=38
Answer: (4)