If k=1n ak=6n3, then k=16 ( ak+1-ak36 )2 is equal to .
Answer
91
Solution
ak=Sk-Sk-1=6k3-6(k-1)3=18k2-18k+6 (also true for k=1: a1=6)
ak+1-ak=18 [(k+1)2-k2 ]-18=18(2k+1)-18=36k
k=16 ( ak+1-ak36 )2= k=16k2
= 6 7 136=91
Answer: 91
If k=1n ak=6n3, then k=16 ( ak+1-ak36 )2 is equal to .
91
ak=Sk-Sk-1=6k3-6(k-1)3=18k2-18k+6 (also true for k=1: a1=6)
ak+1-ak=18 [(k+1)2-k2 ]-18=18(2k+1)-18=36k
k=16 ( ak+1-ak36 )2= k=16k2
= 6 7 136=91
Answer: 91
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