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Sequences and Series · Question 14

JEE Main 2026 (Online) 2nd April Morning ShiftNumericalEasy📈 Topic in 19% papers+4
1

If k=1n ak=6n3, then k=16 ( ak+1-ak36 )2 is equal to .

Answer

91

Solution

ak=Sk-Sk-1=6k3-6(k-1)3=18k2-18k+6 (also true for k=1: a1=6)

ak+1-ak=18 [(k+1)2-k2 ]-18=18(2k+1)-18=36k

k=16 ( ak+1-ak36 )2= k=16k2

= 6 7 136=91

Answer: 91

JEE Main 2026 (Online) 2nd April Morning Shift

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