A siren emitting a sound of frequency 800 Hz moves away from an observer towards a cliff at a speed of 15 m s-1. Then, the frequency of sound that the observer hears in the echo reflected from the cliff is (Take velocity of sound in air = 330 m s-1)
- 838 Hz
- 885 Hz
- 765 Hz
- 800 Hz
Answer
(1) 838 Hz
Solution
The siren (source) moves towards the cliff, so the frequency received by the cliff is
f' = f ( vv - vs )
= 800 330330 - 15
= 800 330315 838 Hz
The cliff reflects this frequency, and both the cliff and the observer are at rest.
Frequency of the echo heard 838 Hz
Answer: (1)