Two cars moving in opposite directions approach each other with speed of 22 m s-1 and 16.5 m s-1 respectively. The driver of the first car blows a horn having a frequency 400 Hz. The frequency heard by the driver of the second car is (velocity of sound is 340 m s-1)
- 361 Hz
- 411 Hz
- 448 Hz
- 350 Hz
Answer
(3) 448 Hz
Solution
Source (first car): vs = 22 m s-1 towards the observer; observer (second car): vo = 16.5 m s-1 towards the source.
f' = f ( v + vov - vs )
= 400 340 + 16.5340 - 22
= 400 356.5318
448 Hz
Answer: (3)