A projectile is thrown upward at an angle 60 with the horizontal. The speed of the projectile is 20 m/s when its direction of motion is 45 with the horizontal. The initial speed of the projectile is m/s.
- 20 3
- 20 2
- 40
- 40 2
Answer
(2) 20 2
Solution
In projectile motion there is no horizontal acceleration, so the horizontal component of velocity stays constant.
u 60 = v 45
u 12 = 20 1 2
u = 40 2
u = 20 2 m/s
Answer: (2)