An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen. After some oxygen is withdrawn from the cylinder, its gauge pressure drops to 11 atmospheric pressures at temperature 27 . The mass of the oxygen withdrawn from the cylinder is nearly equal to: [Given, R = 10012 J mol-1 K-1, and molecular mass of O2 = 32, 1 atm pressure = 1.01 105 N/m2]
- 0.116 kg
- 0.156 kg
- 0.125 kg
- 0.144 kg
Answer
(1) 0.116 kg
Solution
Gauge pressure = 11 atm, so absolute pressure P = 11 + 1 = 12 atm
P = 12 1.01 105 = 1.212 106 N/m2
V = 30 L = 3 10-2 m3, T = 300 K
Moles left: n2 = PVRT = 1.212 106 3 10-2 10012 300
n2 = 363602500 = 14.54
Moles withdrawn: n = 18.20 - 14.54 = 3.66
Mass withdrawn: m = 3.656 32 117 g
m 0.116 kg
Answer: (1)