A container has two chambers of volumes V1 = 2 litres and V2 = 3 litres separated by a partition made of a thermal insulator. The chambers contain n1 = 5 and n2 = 4 moles of ideal gas at pressures p1 = 1 atm and p2 = 2 atm, respectively. When the partition is removed, the mixture attains an equilibrium pressure of
- 1.4 atm
- 1.8 atm
- 1.3 atm
- 1.6 atm
Answer
(4) 1.6 atm
Solution
The container is isolated, so the total internal energy is conserved. For an ideal gas U = f2nRT = f2pV.
f2p1V1 + f2p2V2 = f2p(V1 + V2)
p = p1V1 + p2V2V1 + V2 = 1 2 + 2 32 + 3 = 85 = 1.6 atm
Answer: (4)