Two radiations of photons energies 1 eV and 2.5 eV, successively illuminate a photosensitive metallic surface of work function 0.5 eV. The ratio of the maximum speeds of the emitted electrons is
- 1 : 4
- 1 : 2
- 1 : 1
- 1 : 5
Answer
(2) 1 : 2
Solution
Einstein's photoelectric equation: Kmax = 12mvmax2 = h - 0
K1 = 1 - 0.5 = 0.5 eV
K2 = 2.5 - 0.5 = 2.0 eV
∵ vmax Kmax
⇒ v1v2 = 0.52.0 = 14 = 12
∴ v1 : v2 = 1 : 2
Answer: (2)