A 200 W sodium street lamp emits yellow light of wavelength 0.6 . Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is
- 1.5 1020
- 6 1018
- 62 1020
- 3 1019
Answer
(1) 1.5 1020
Solution
Light power emitted = 25\% of 200 W = 50 W
Energy of one photon:
E = hc = 6.63 10-34 3 1080.6 10-6
= 3.3 10-19 J
Number of photons per second:
n = PE = 503.3 10-19
1.5 1020
Answer: (1)