A particle moves from a point (-2 i+5 j ) to (4 j+3 k ) when a force of (4 i+3 j ) N is applied. How much work has been done by the force ?
- 8 J
- 11 J
- 5 J
- 2 J
Answer
(3) 5 J
Solution
Displacement d = (4 j+3 k ) - (-2 i+5 j )
d = 2 i - j + 3 k
W = F d = (4 i+3 j ) (2 i - j + 3 k )
W = 8 - 3 + 0 = 5 J
Answer: (3)