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Solutions · Question 12

NEET (UG) 2022 (Phase 2)MCQEasy📈 Topic in 38% papers+4−1
1

KH value for some gases at the same temperature 'T' are given : [figure] where KH is Henry's Law constant in water. The order of their solubility in water is :

  1. HCHO < CH4 < CO2 < Ar
  2. Ar < CO2 < CH4 < HCHO
  3. Ar < CH4 < CO2 < HCHO
  4. HCHO < CO2 < CH4 < Ar

Answer

(2) Ar < CO2 < CH4 < HCHO

Solution

Henry's law: p = KH x

x = pKH

As per NCERT, at the same partial pressure, higher the value of KH, lower is the solubility of the gas in the liquid.

KH: Ar (40.3) > CO2 (1.67) > CH4 (0.413) > HCHO (1.83 10-5)

Solubility: Ar < CO2 < CH4 < HCHO

Answer: (2)

NEET (UG) 2022 (Phase 2)

Keep practising — Solutions

2

The following solutions were prepared by dissolving 10 g of glucose ( C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose ( C12H22O11) in 250 ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :

  1. P3 > P1 > P2
  2. P2 > P1 > P3
  3. P1 > P2 > P3
  4. P2 > P3 > P1
NEET (UG) 2021
3

The correct option for the value of vapour pressure of a solution at 45 C with benzene to octane in molar ratio 3 : 2 is : [At 45 C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume ideal solution]

  1. 350 mm of Hg
  2. 160 mm of Hg
  3. 168 mm of Hg
  4. 336 mm of Hg
NEET (UG) 2021
4

The freezing point depression constant (Kf) of benzene is 5.12 K kg mol-1. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is rounded off upto two decimal places :

  1. 0.80 K
  2. 0.40 K
  3. 0.60 K
  4. 0.20 K
NEET (UG) 2020
5

The mixture which shows positive deviation from Raoult's law is :

  1. Benzene + Toluene
  2. Acetone + Chloroform
  3. Chloroethane + Bromoethane
  4. Ethanol + Acetone
NEET (UG) 2020
6

For an ideal solution, the correct option is :

  1. mix H = 0 at constant T and P
  2. mix G = 0 at constant T and P
  3. mix S = 0 at constant T and P
  4. mix V 0 at constant T and P
NEET (UG) 2019
7

The mixture that forms maximum boiling azeotrope is :

  1. Ethanol + Water
  2. Acetone + Carbon disulphide
  3. Heptane + Octane
  4. Water + Nitric acid
NEET (UG) 2019
8

If molality of the dilute solution is doubled, the value of molal depression constant (Kf) will be

  1. halved
  2. tripled
  3. unchanged
  4. doubled.
NEET 2017
9

Which of the following is dependent on temperature?

  1. Molarity
  2. Mole fraction
  3. Weight percentage
  4. Molality
NEET 2017
10

Which of the following statements about the composition of the vapour over an ideal 1 : 1 molar mixture of benzene and toluene is correct? Assume that the temperature is constant at 25 . (Given, vapour pressure data at 25 , benzene = 12.8 kPa, toluene = 3.85 kPa)

  1. The vapour will contain equal amounts of benzene and toluene.
  2. Not enough information is given to make a prediction.
  3. The vapour will contain a higher percentage of benzene.
  4. The vapour will contain a higher percentage of toluene
NEET 2016 (Phase 1)
11

At 100 the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be

  1. 102
  2. 103
  3. 101
  4. 100
NEET 2016 (Phase 1)

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