If the mean deviation about the median of the numbers k, 2k, 3k, , 1000k is 500, then k2 is equal to :
- 1
- 16
- 9
- 4
Answer
(4) 4
Solution
There are 1000 numbers, so the median M = 500k + 501k2 = 500.5k
M.D.(M) = 11000 i=11000 |ik - 500.5k| = |k|1000 i=11000 |i - 500.5|
The deviations are 0.5, 1.5, , 499.5, each occurring twice:
|i - 500.5| = 2(0.5 + 1.5 + + 499.5) = 2 5002(0.5 + 499.5)
= 250000
M.D. = |k| 2500001000 = 250|k| = 500
|k| = 2 k2 = 4
Answer: (4)