If the mean and the variance of the data array|l|c|c|c|c| Class & 4-8 & 8-12 & 12-16 & 16-20 \ Frequency & 3 & & 4 & 7 \ array are and 19 respectively, then the value of + is :
- 21
- 19
- 18
- 20
Answer
(2) 19
Solution
Class marks: xi = 6, 10, 14, 18; frequencies: 3, , 4, 7; N = 14 +
fi xi = 18 + 10 + 56 + 126 = 200 + 10
fi xi2 = 108 + 100 + 784 + 2268 = 3160 + 100
Variance: fi xi2N - ( fi xiN )2 = 19
(3160 + 100 )(14 + ) - (200 + 10 )2 = 19(14 + )2
4240 + 560 = 3724 + 532 + 19 2
19 2 - 28 - 516 = 0
( - 6)(19 + 86) = 0 = 6 (frequency is positive)
= 200 + 6020 = 13
+ = 6 + 13 = 19
Answer: (2)