The heat of combustion of solid benzoic acid at constant volume is -321.30 kJ at 27 C. The heat of combustion at constant pressure is (-321.30 - xR) kJ, the value of x is .
Answer
150
Solution
C6H5COOH(s) + 152O2(g) 7CO2(g) + 3H2O(l)
ng = 7 - 152 = - 12 (only gases counted)
H = U + ngRT
= -321.30 + (- 12 ) R 300
= -321.30 - 150R ⇒ x = 150
Answer: 150