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Thermodynamics

JEE Main 2024 (Online) 5th April Morning ShiftMCQEasy📈 Topic in 17% papers+4−1
Ques. 1JEE Main 2024, 5 April (Morning Shift)

Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R) In the light of the above statements, choose the correct answer from the options given below.

  1. (A) is true but (R) is false
  2. Both (A) and (R) are true and (R) is the correct explanation of (A)
  3. Both (A) and (R) are true but (R) is not the correct explanation of (A)
  4. (A) is false but (R) is true

Answer

(2) Both (A) and (R) are true and (R) is the correct explanation of (A)

Solution

Strong acid and strong base are completely ionised ⇒ the only change is

H+(aq) + -OH(aq) H2O(l), neutH = -57 kJ mol-1

∵ no energy is spent on ionisation, every such pair gives the same value ⇒ (A) is true

(R) defines exactly this change: 1 mol H+ + 1 mol -OH 1 mol H2O

⇒ (R) is true and is the correct explanation of (A)

Answer: (2)

Keep practising — Thermodynamics

Ques. 2JEE Main 2024, 5 April (Morning Shift)

The heat of combustion of solid benzoic acid at constant volume is -321.30 kJ at 27 C. The heat of combustion at constant pressure is (-321.30 - xR) kJ, the value of x is .

Ques. 3JEE Main 2024, 5 April (Evening Shift)

Combustion of 1 mole of benzene is expressed as C6H6(l) + 152O2(g) 6CO2(g) + 3H2O(l). The standard enthalpy of combustion of 2 mol of benzene is −'x' kJ. x = . Given : 1. Standard Enthalpy of formation of 1 mol of C6H6(l), for the reaction 6C(graphite) + 3H2(g) C6H6(l) is 48.5 kJ mol-1. 2. Standard Enthalpy of formation of 1 mol of CO2(g), for the reaction C(graphite) + O2(g) CO2(g) is -393.5 kJ mol-1. 3. Standard Enthalpy of formation of 1 mol of H2O(l), for the reaction H2(g) + 12O2(g) H2O(l) is -286 kJ mol-1.

Ques. 4JEE Main 2024, 4 April (Morning Shift)

The enthalpy of formation of ethane (C2H6) from ethylene by addition of hydrogen where the bond-energies of C-H, C-C, C=C, H-H are 414 kJ, 347 kJ, 615 kJ and 435 kJ respectively is − kJ

Ques. 5JEE Main 2024, 4 April (Evening Shift)

Three moles of an ideal gas are compressed isothermally from 60 L to 20 L using constant pressure of 5 atm. Heat exchange Q for the compression is - Lit. atm.

Ques. 6JEE Main 2024, 1 February (Morning Shift)

Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following :

  1. q = 0, T = 0, w = 0
  2. q = 0, T 0, w = 0
  3. q 0, T = 0, w = 0
  4. q = 0, T < 0, w 0
Ques. 7JEE Main 2024, 1 February (Evening Shift)

For a certain reaction at 300 K, K = 10, then for the same reaction is − 10-1 kJ mol-1. (Given R = 8.314 J K-1 mol-1)

Ques. 8JEE Main 2024, 31 January (Morning Shift)

Consider the following reaction at 298 K: 32O2(g) O3(g); KP = 2.47 10-29. rG for the reaction is kJ. (Given R = 8.314 JK-1 mol-1)

Ques. 9JEE Main 2024, 31 January (Evening Shift)

If 5 moles of an ideal gas expands from 10 L to a volume of 100 L at 300 K under isothermal and reversible condition then work, w, is −x J. The value of x is . (Given R = 8.314 J K-1 mol-1)

Ques. 10JEE Main 2024, 30 January (Morning Shift)

[figure] An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path A B C A as shown in the diagram above. The total work done in the process is J.

Ques. 11JEE Main 2024, 30 January (Evening Shift)

Two reactions are given below: 2Fe(s) + 32O2(g) Fe2O3(s), H = -822 kJ/mol C(s) + 12O2(g) CO(g), H = -110 kJ/mol Then enthalpy change for following reaction 3C(s) + Fe2O3(s) 2Fe(s) + 3CO(g) is kJ/mol.

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