An engine pumps water continuously through a hose. Water leaves the hose with a velocity v and m is the mass per unit length of the water jet. What is the rate at which kinetic energy is imparted to water?
- mv3
- 12mv2
- 12m2v2
- 12mv3
Answer
(4) 12mv3
Solution
Mass of water leaving per second = (mass per unit length) × (length per second)
dMdt = mv
Rate of KE imparted = 12 ( dMdt )v2
= 12(mv)v2
Rate of KE = 12mv3
Answer: (4)