A body of mass 1 kg is thrown upwards with a velocity 20 m s-1. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? ( g = 10 m s-2)
- 30 J
- 40 J
- 10 J
- 20 J
Answer
(4) 20 J
Solution
Initial KE = 12mv2 = 12 1 202 = 200 J
PE at the highest point = mgh = 1 10 18 = 180 J
Energy lost due to air friction = 200 - 180 = 20 J
Answer: (4)