A ball moving with velocity 2 m/s collides head on with another stationary ball of double the mass. If the coefficient of restitution is 0.5, then their velocities (in m/s) after collision will be
- 0, 1
- 1, 1
- 1, 0.5
- 0, 2
Answer
(1) 0, 1
Solution
Let masses be m and 2m; u1 = 2 m/s, u2 = 0.
Momentum conservation:
m(2) = mv1 + 2mv2
v1 + 2v2 = 2 ...(i)
Coefficient of restitution:
e = v2 - v1u1 - u2
v2 - v1 = 0.5 2 = 1 ...(ii)
Adding (i) and (ii): 3v2 = 3
v2 = 1 m/s, v1 = 0
Answer: (1)