Identify the correct truth table of the given logic circuit. [figure]
- arrayccc A & B & Y \ 0 & 0 & 0 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 0 array
- arrayccc A & B & Y \ 0 & 0 & 0 \ 0 & 1 & 1 \ 1 & 0 & 1 \ 1 & 1 & 0 array
- arrayccc A & B & Y \ 0 & 0 & 1 \ 0 & 1 & 1 \ 1 & 0 & 1 \ 1 & 1 & 0 array
- arrayccc A & B & Y \ 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 0 array
Answer
(1) arrayccc A & B & Y \ 0 & 0 & 0 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 0 array
Solution
Upper gate: AND gate with both inputs joined to A output = A A = A
Lower gate: NAND gate output = A B
Next gate: AND with inputs joined output = A B
Final AND gate:
Y = A A B = A ( A + B) = A B
Truth table: (0, 0) → 0, (0, 1) → 0, (1, 0) → 1, (1, 1) → 0
Answer: (1)