The output voltage in the following circuit is (Consider ideal diode case) [figure]
- 0 V
- +5 V
- −5 V
- 10 V
Answer
(1) 0 V
Solution
D2: anode joined to +5 V through the resistor, cathode earthed ⇒ forward biased ⇒ conducts.
An ideal conducting diode has zero voltage drop ⇒ Vout = 0 V.
D1: anode at 0 V (output point), cathode at +5 V ⇒ reverse biased ⇒ does not conduct.
Vout = 0 V
Answer: (1)