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Semiconductor Electronics · Question 23

JEE Main 2025 (Online) 7th April Morning ShiftMCQEasy📈 Topic in 23% papers+4−1
1

In the following circuit, the reading of the ammeter will be (Take Zener breakdown voltage = 4 V) [figure]

  1. 60 mA
  2. 80 mA
  3. 10 mA
  4. 24 mA

Answer

(3) 10 mA

Solution

The Zener diode's cathode is connected to the positive terminal side of the 12 V source, so it is reverse biased.

∵ The voltage available (12 V) is more than the breakdown voltage, the Zener conducts and holds the voltage across it at 4 V.

The 400 resistor (with the ammeter) is in parallel with the Zener:

V400 = 4 V

⇒ I = 4400 A = 0.01 A = 10 mA

(Check: current through 100 = 12 - 4100 = 80 mA > 10 mA, so the Zener carries 70 mA and stays in breakdown.)

Answer: (3)

JEE Main 2025 (Online) 7th April Morning Shift

Keep practising — Semiconductor Electronics

2

Consider the following logic circuit. [figure] The output is Y = 0 when :

  1. A = 1 and B = 0
  2. A = 0 and B = 0
  3. A = 1 and B = 1
  4. A = 0 and B = 1
JEE Main 2025 (Online) 7th April Evening Shift
3

The Boolean expression Y = A BC + A C can be realised with which of the following gate configurations. Choose the correct answer from the options given below:

  1. B, C Only
  2. A, B, C Only
  3. A, B Only
  4. A, C Only
JEE Main 2025 (Online) 4th April Morning Shift
4

Consider an n-type semiconductor in which ne and nh are number of electrons and holes, respectively. Choose the correct answer from the options given below :

  1. (A), (B), (E) only
  2. (A), (C), (E) only
  3. (A), (B), (C) only
  4. (A), (C), (D) only
JEE Main 2025 (Online) 4th April Evening Shift
5

Choose the correct logic circuit for the given truth table having inputs A and B. [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2025 (Online) 3rd April Morning Shift
6

The truth table corresponding to the circuit given below is: [figure]

  1. arrayccc A & B & C \ 0 & 0 & 0 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 1 array
  2. arrayccc A & B & C \ 0 & 0 & 1 \ 1 & 0 & 0 \ 0 & 1 & 0 \ 1 & 1 & 0 array
  3. arrayccc A & B & C \ 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \ 1 & 1 & 0 array
  4. arrayccc A & B & C \ 0 & 0 & 0 \ 1 & 0 & 0 \ 0 & 1 & 0 \ 1 & 1 & 1 array
JEE Main 2025 (Online) 3rd April Evening Shift
7

A zener diode with 5 V zener voltage is used to regulate an unregulated dc voltage input of 25 V. For a 400 resistor connected in series, the zener current is found to be 4 times load current. The load current (IL) and load resistance (RL) are :

  1. IL = 0.02 mA; RL = 250
  2. IL = 10 A; RL = 0.5
  3. IL = 10 mA; RL = 500
  4. IL = 20 mA; RL = 250
JEE Main 2025 (Online) 2nd April Morning Shift
8

In the digital circuit shown in the figure, for the given inputs the P and Q values are : [figure]

  1. P = 0, Q = 1
  2. P = 1, Q = 0
  3. P = 0, Q = 0
  4. P = 1, Q = 1
JEE Main 2025 (Online) 2nd April Evening Shift
9

[figure] For the circuit shown above, equivalent GATE is :

  1. NOT gate
  2. NAND gate
  3. AND gate
  4. OR gate
JEE Main 2025 (Online) 29th January Morning Shift
10

Which of the following circuits has the same output as that of the given circuit? [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2025 (Online) 28th January Morning Shift
11

[figure] In the circuit shown here, assuming threshold voltage of diode is negligibly small, then voltage VAB is correctly represented by:

  1. [figure]
  2. [figure]
  3. VAB would be zero at all times.
  4. [figure]
JEE Main 2025 (Online) 28th January Evening Shift

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