Decreasing order of stability of O2, O2-, O2+ and O22- is
- O22- > O2- > O2 > O2+
- O2 > O2+ > O22- > O2-
- O2- > O22- > O2+ > O2
- O2+ > O2 > O2- > O22-
Answer
(4) O2+ > O2 > O2- > O22-
Solution
Bond order = 12(Nb - Na); O2 has 16 electrons with Nb = 10.
O2+ (15 e⁻): Na = 5 ⇒ B.O. = 10 - 52 = 2.5
O2 (16 e⁻): Na = 6 ⇒ B.O. = 10 - 62 = 2
O2- (17 e⁻): Na = 7 ⇒ B.O. = 10 - 72 = 1.5
O22- (18 e⁻): Na = 8 ⇒ B.O. = 10 - 82 = 1
∵ Stability increases with bond order,
∴ O2+ > O2 > O2- > O22-
Answer: (4)