A rod PQ of mass M and length L is hinged at end P. The rod is kept horizontal by a massless string tied to point Q as shown in figure. When string is cut, the initial angular acceleration of the rod is [figure]
- 2gL
- 2g3L
- 3g2L
- gL
Answer
(3) 3g2L
Solution
Just after the string is cut, the only torque about P is due to the weight acting at the centre of the rod:
= Mg L2
Moment of inertia of the rod about the end P: I = ML23
= I
= MgL/2ML2/3 = 3g2L
Answer: (3)