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System of Particles and Rotational Motion · Question 49

AIPMT 2012 (Mains)MCQHard📈 Topic in 12% papers+4−1
1

A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kg m2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 m s-1 relative to the ground. Time taken by the man to complete one revolution is

  1. s
  2. 3 2 s
  3. 2 s
  4. 2 s

Answer

(3) 2 s

Solution

No external torque about the axle angular momentum is conserved (initially zero).

mvR = I p

50 1 2 = 200 p

p = 0.5 rad s-1 (platform turns opposite to the man)

Angular speed of man (w.r.t. ground): m = vR = 12 = 0.5 rad s-1

Angular speed of man relative to the platform: rel = m + p = 1 rad s-1

time for one revolution on the platform T = 2 rel = 2 s

Answer: (3)

AIPMT 2012 (Mains)

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