A vertical spring with force constant k is fixed on a table. A ball of mass m at a height h above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance d. The net work done in the process is
- mg(h + d) - 12kd2
- mg(h - d) - 12kd2
- mg(h - d) + 12kd2
- mg(h + d) + 12kd2
Answer
(1) mg(h + d) - 12kd2
Solution
The ball falls through a total height (h + d).
Work done by gravity: Wg = mg(h + d)
Work done by the spring force (opposite to displacement): Ws = - 12kd2
∴ Net work done = mg(h + d) - 12kd2
Answer: (1)