The number of seven-digit numbers, that can be formed by using the digits 1, 2, 3, 5 and 7 such that each digit is used at least once, is :
- 15400
- 17800
- 16800
- 29400
Answer
(3) 16800
Solution
All 5 digits must appear in 7 places, so 2 places are extra. Two cases:
Case I: one digit used 3 times, the other four once each.
Choose the digit: 5 ways; arrangements = 7!3!=840
5 840=4200
Case II: two digits used twice each, the other three once each.
Choose the two digits: 5C2=10; arrangements = 7!2! 2!=1260
10 1260=12600
∴ Total =4200+12600=16800
Answer: (3)