Let A=\(a, b, c) : a, b, c are non-negative integers and a+b+2c=22\. Then n(A) is equal to :
- 121
- 124
- 144
- 169
Answer
(3) 144
Solution
a+b=22-2c 0 c=0, 1, 2, , 11
For a fixed c, a+b=N has N+1 non-negative solutions 23-2c solutions
n(A)= c=011(23-2c)=23+21+19+ +1
=122=144 (sum of the first 12 odd numbers)
Answer: (3)