Rate constants of a reaction at 500 K and 700 K are 0.04 s-1 and 0.14 s-1, respectively; then, activation energy of the reaction is : (Given: 3.5 = 0.5441, R = 8.31 J K-1 mol-1)
- 182310 J
- 18500 J
- 18219 J
- 18030 J
Answer
(3) 18219 J
Solution
k2k1 = Ea2.303R ( T2 - T1T1 T2 )
k2k1 = 0.140.04 = 3.5
0.5441 = Ea2.303 8.31 200500 700
Ea = 0.5441 2.303 8.31 1750
1.822 104 J
Ea 18219 J (nearest option)
Answer: (3)