For a chemical reaction 4A + 3B 6C + 9D Rate of formation of C is 6 10-2 mol L-1 s-1 and rate of disappearance of A is 4 10-2 mol L-1 s-1. The rate of reaction and amount of B consumed in interval of 10 seconds, respectively will be :
- 10 10-2 mol L-1 s-1 and 30 10-2 mol L-1
- 1 10-2 mol L-1 s-1 and 30 10-2 mol L-1
- 10 10-2 mol L-1 s-1 and 10 10-2 mol L-1
- 1 10-2 mol L-1 s-1 and 10 10-2 mol L-1
Answer
(2) 1 10-2 mol L-1 s-1 and 30 10-2 mol L-1
Solution
Rate = - 14 d[A]dt = - 13 d[B]dt = 16 d[C]dt = 19 d[D]dt
Rate = 16 6 10-2 = 1 10-2 mol L-1 s-1
(check: 14 4 10-2 = 1 10-2)
Rate of consumption of B = 3 1 10-2 = 3 10-2 mol L-1 s-1
B consumed in 10 s = 3 10-2 10
= 30 10-2 mol L-1
Answer: (2)