The half life of a first order reaction is 2000 years. If the concentration after 8000 years is 0.02 M, then the initial concentration was :
- 0.04 M
- 0.16 M
- 0.32 M
- 0.08 M
Answer
(3) 0.32 M
Solution
Number of half-lives, n = 80002000 = 4
For a first order reaction, [A] = [A]02n
[A]0 = [A] 2n
= 0.02 24
= 0.02 16 = 0.32 M
Answer: (3)