If the molar conductivity ( m) of a 0.050 mol L-1 solution of a monobasic weak acid is 90 S cm2 mol-1, its extent (degree) of dissociation will be [Assume + = 349.6 S cm2 mol-1 and - = 50.4 S cm2 mol-1.]
- 0.225
- 0.215
- 0.115
- 0.125
Answer
(1) 0.225
Solution
By Kohlrausch's law: m = + + - = 349.6 + 50.4 = 400 S cm2 mol-1
= m m = 90400 = 0.225
Answer: (1)