Two half cell reactions are given below. Co3+ + e- Co2+, E0 Co2+/Co3+ = -1.81 V 2Al3+ + 6e- 2Al(s), E0 Al/Al3+ = +1.66 V The standard EMF of a cell with feasible redox reaction will be :
- -3.47 V
- +7.09 V
- +0.15 V
- +3.47 V
Answer
(4) +3.47 V
Solution
The given potentials are written for the couples Co2+/Co3+ and Al/Al3+, i.e. they are oxidation potentials.
⇒ Reduction potentials: E0 Co3+/Co2+ = +1.81 V and E0 Al3+/Al = -1.66 V
∵ Co3+ has the higher reduction potential, it is reduced at the cathode and Al is oxidised at the anode.
Cell reaction: Al(s) + 3Co3+ Al3+ + 3Co2+
E0cell = E0cathode - E0anode
= +1.81 - (-1.66)
= +3.47 V
∴ Positive EMF confirms the reaction is feasible.
Answer: (4)