A mixture of N2 and Ar gases in a cylinder contains 7 g of N2 and 8 g of Ar. If the total pressure of the mixture of the gases in the cylinder is 27 bar, the partial pressure of N2 is : [Use atomic masses (in g mol-1) : N = 14, Ar = 40]
- 12 bar
- 15 bar
- 18 bar
- 9 bar
Answer
(2) 15 bar
Solution
nN2 = 728 = 0.25 mol
nAr = 840 = 0.20 mol
⇒ xN2 = 0.250.25 + 0.20 = 59
By Dalton's law of partial pressures, pN2 = xN2 ptotal
⇒ pN2 = 59 27 bar
= 15 bar
Answer: (2)