Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape?
- 3/8
- 1/2
- 1/8
- 1/4
Answer
(3) 1/8
Solution
By Graham's law, for the same time the amount escaping is proportional to the rate:
nO2 nH2 = MH2 MO2
= 232 = 14
Fraction of hydrogen escaped = 12
Fraction of oxygen escaped = 14 12 = 18
Answer: (3)