A certain gas takes three times as long to effuse out as helium. Its molecular mass will be
- 27 u
- 36 u
- 64 u
- 9 u
Answer
(2) 36 u
Solution
Graham's law: rate of effusion r 1 M
∵ For the same volume, time taken t 1r M
⇒ tgastHe = MMHe
⇒ 3 = M4
⇒ M = 9 4 = 36 u
Answer: (2)