[figure] In the above diagram, a strong bar magnet is moving towards solenoid-2 from solenoid-1. The direction of induced current in solenoid-1 and that in solenoid-2, respectively, are through the directions:
- AB and DC
- BA and CD
- AB and CD
- BA and DC
Answer
(1) AB and DC
Solution
By Lenz's law the induced current opposes the motion of the magnet.
Solenoid-1: the N-pole moves away from its right end, so that end becomes an S-pole (attracting the magnet back). With the winding shown, this needs current from A to B, i.e. AB.
Solenoid-2: the S-pole approaches its left end, so that end becomes an S-pole (repelling the magnet). This needs current in the opposite sense, from D to C, i.e. DC.
Answer: (1)