The magnetic energy stored in an inductor of inductance 4 carrying a current of 2 A is :
- 4 mJ
- 8 mJ
- 8
- 4
Answer
(3) 8
Solution
U = 12LI2
= 12 4 10-6 22
= 8 10-6 J = 8
Answer: (3)
The magnetic energy stored in an inductor of inductance 4 carrying a current of 2 A is :
(3) 8
U = 12LI2
= 12 4 10-6 22
= 8 10-6 J = 8
Answer: (3)
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