A square loop of side 1 m and resistance 1 is placed in a magnetic field of 0.5 T. If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is
- 2 weber
- 0.5 weber
- 1 weber
- Zero weber
Answer
(2) 0.5 weber
Solution
Plane of the loop perpendicular to the field area vector A is parallel to B ( = 0 ).
= BA 0 = 0.5 (1)2 1
= 0.5 Wb
(The resistance of the loop does not affect the flux.)
Answer: (2)