Let us consider two solenoids A and B, made from same magnetic material of relative permeability r and equal area of cross-section. Length of A is twice that of B and the number of turns per unit length in A is half that of B. The ratio of self inductances of the two solenoids, LA : LB is
- 1 : 2
- 2 : 1
- 8 : 1
- 1 : 8
Answer
(1) 1 : 2
Solution
Self-inductance of a solenoid: L = 0 r n2 A l
Given lA = 2lB, nA = nB2, same A and r:
LALB = ( nAnB )2 lAlB = 14 2 = 12
LA : LB = 1 : 2
Answer: (1)