Two short dipoles (A, B), A having charges 2 and length 1 cm and B having charges 4 and length 1 cm are placed with their centres 80 cm apart as shown in the figure. The electric field at a point P, equi-distant from the centres of both dipoles is N/C. [figure]
- 916 2 105
- 916 2 104
- 9 2 104
- 4.5 2 104
Answer
(2) 916 2 104
Solution
P is 40 cm = 0.4 m from each centre; both dipoles are short (r length).
pA = 2 10-6 10-2 = 2 10-8 C m, pB = 4 10-6 10-2 = 4 10-8 C m
P lies on the axis of A: EA = 2kpAr3 = 2 9 109 2 10-8(0.4)3 = 3600.064 = 5625 N/C (horizontal)
P lies on the equatorial line of B: EB = kpBr3 = 9 109 4 10-8(0.4)3 = 5625 N/C (vertical)
EA EB E = EA2 + EB2 = 5625 2 N/C
= 916 2 104 N/C
Answer: (2)